Koda: |
Dim aaa As Decimal
aaa = 12345.1234 MsgBox(CLng((aaa - CLng(aaa)) * 10000)) |
Krampus je napisal/a: | ||
|
Koda: |
r = 8.51851919533492
s = Str(r) 'Pretvorba v string vejica = InStr(1, s, ".") 'poiščemo decimalno vejico(piko) decimalke = Mid(s, vejica + 1, 4) 'In iz stringa vzamemo 4 znake za vejico |
Koda: |
INT((ABS(3210,123456789)-INT(ABS(3210,123456789)))*10000)
INT((ABS(8,51851919533492)-INT(ABS(8,51851919533492)))*10000) |